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Iotaq
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There may be an obvious way to do this, but i sure haven't found it. How many turns are there in a game? (If it depends on difficulty do whatever)
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Iotaq
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P.S. Iotaq=Joony, so this ain't my first post
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Aeson
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orangesoda
Nov 2001 time: 22:21
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It is 540.
For an Excel conversion from date to turn number: (has to be a valid Civ3 date, in column D in this case)
=IF($D:$D > 1950,$D:$D - 1950 + 440, IF($D:$D > 1750, (($D:$D - 1750) / 2) + 340, IF($D:$D > 1250, (($D:$D - 1250) / 5) + 240, IF($D:$D > 250, (($D:$D - 250) / 10) + 140, IF($D:$D > -750, (($D:$D +750) / 20) + 90, IF($D:$D > -1750, (($D:$D + 1750) / 25) + 50, IF($D:$D > -2750, (($D:$D + 2750) / 40) + 50, ($D:$D + 4000) / 50)))))))
Not very pretty, but it works.
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Aeson
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orangesoda
Nov 2001 time: 22:21
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A table:
4000BC 1 turn, N/A years from previous turn
3950BC - 2750BC 25 turns, 50 years from previous turn
2710BC - 1750BC 25 turns, 40 years from previous turn
1725BC - 750BC 40 turns, 25 years from previous turn
730BC - 250AD 50 turns, 20 years from previous turn
260AD - 1250AD 100 turns, 10 years from previous turn
1255AD - 1750AD 100 turns, 5 years from previous turn
1752AD - 1950AD 100 turns, 2 years from previous turn
1951AD - 2050AD 100* turns, 1 year from previous turn
*2050AD is not a full turn, only a few automated events happen.
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Iotaq
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I didn't think there was anything wrong with that! Anyway i will NEVER log in as joony again, so you can take that off. Woops!
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