15-04-2003 03:59									#1
	This math question can't be very hard, right? Support Apolyton, buy Civilization III: Complete

If we assume that we use 15% more money on something every year from 1978 to 1987, how do we figure out the total increase during the time span?

	15-04-2003 04:01									#2
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Very simple.

Money = (StartMoney X (1.15)^{# of years}) - StartMoney

	15-04-2003 04:08									#3
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Thank you sir, that was most welcome.

	15-04-2003 04:08									#4
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You've had that "world leader" a bit long Monk dear boy...

	15-04-2003 04:12									#5
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Hello there old chap! How are things? I figure no harm will be done threadjacking this one.

I am absolute incapable of finding or creating avatars, so I'm stuck with whatever I've got until Stefu's mercy provides another. You're absolutely right though, I have to find another trendy leader.

	15-04-2003 04:15									#6
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Hmm... who's trendy enough to be in a Monk avatar?

	15-04-2003 04:19									#7
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I give you the President of Kazahkstan.




Find more leaders (as of 2000) here:

http://edition.cnn.com/2000/US/09/0...mit.names.reut/

	15-04-2003 04:20									#8
	Avatar Enlargement: We've got the solution

Erm... don't tell anybody, but I've always liked Joschka Fischer, I think he seems like a genuinely cool dude. Then again, my German friend (a CSU supporter) tells me I'd think differently if I had a clue. What led you to that avatar?

	15-04-2003 04:21									#9
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I like this one, the PM of Chad.



He has a mad stare there.

	15-04-2003 04:21									#10
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Isn't the answer rather

StartMoney * (1 + 1.15 + 1.15² + 1.15³ + ... + 1.15⁹ - 10) ?

This is not what Asher wrote, or did I understand the problem wrong. For example, you spend 1000 in 1978, 1150 in 1979, 1322.50 in 1980 etc. and you ask, how many more than 1000 per year you spent in the end? If so, Ashers solution sounds wrong.

	15-04-2003 04:22									#11
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Wow, the Kazahk Prez. You know what, that could work. I'm checking out a couple others right now, thanks a lot for the link.

	15-04-2003 04:25									#12
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Aaaah, no, Sir Ralph!

Why'd you have to go and make things so complicated?

Your interpretation is, I think, correct, though I can't say if your answer is. But now I'm confusing myself and probably the rest of you too.

	15-04-2003 04:29									#13
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quote: Originally posted by Sir Ralph Isn't the answer rather StartMoney * (1 + 1.15 + 1.15² + 1.15³ + ... + 1.159 - 10) ? This is not what Asher wrote, or did I understand the problem wrong. For example, you spend 1000 in 1978, 1150 in 1979, 1322.50 in 1980 etc. and you ask, how many more than 1000 per year you spent in the end? If so, Ashers solution sounds wrong.

The increase is what Asher wrote. The cumulative increase is what you have written. Not sure which Monk was after though.

	15-04-2003 04:29									#14
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If my interpretation is correct, the my solution should be correct too. In this case, the solution is

SUM^{(n from 0 to 9)}(1.15ⁿ) - SUM^{(n from 0 to 9)}(1)

The former term is 1 + 1.15 + 1.15² ..., the latter term is 10.

	15-04-2003 04:30									#15
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Monk :
Who's on your avatar ?

Others :
Can you continue the following pattern ?

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	15-04-2003 04:32									#16
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quote: Originally posted by Big Crunch The increase is what Asher wrote. The cumulative increase is what you have written. Not sure which Monk was after though.

Well, he wrote total increase...

	15-04-2003 04:35									#17
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Edit:

Actually that was wrong and forever immortalised in the following post.

Last edited by Dauphin on 15-04-2003 at 04:46

	15-04-2003 04:37									#18
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quote: Originally posted by Big Crunch quote: SUM(n from 0 to 9)(1.15n) - SUM(n from 0 to 9)(1) or 1/r[1 + 1/(1-r)n] Where r is the % increase each year and n is the number of years.

Please be merciful with me, it's 1:45am, and I have digged my formula books very deep under.

	15-04-2003 04:41									#19
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Okay, I'm sorry if I've been unclear on some points. The task was to compare the 1978 and 1987 numbers - that is, to find out how many percent constituted the total increase from 1978 to 1987 assuming a 15% increase every year. I think the answer would have to be 22.5%.

	15-04-2003 05:39									#20
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I assumed what he was looking for was equivalent to compound interest...

I don't know if that's what he's looking for, but that's how I interpreted it.

	15-04-2003 08:17									#21
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way too classic by now