27-10-2002 04:15									#271
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quote: Originally posted by Ramo c1/c2ln(5/4) = 2 c1/c2ln(6/5) = 1 Solve that (which I can't be arsed to do ).

Those equations are not compatable.

	27-10-2002 08:34									#272
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quote: Originally posted by Ignorance 12 is XII in roman numerals. \/ I I /\ I I Split in two \/ I I ------ /\ I I VII is 7

But /\II don't mean anything.

	27-10-2002 09:18									#273
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I agree with SD.

	27-10-2002 10:50									#274
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quote: Those equations are not compatable.

It should be 5 - T, where T is the starting time, not 5, and so forth.

But ignoring the infinite velocity problem, I worked it out and got crap. I think the problem is contradictory.

	27-10-2002 10:57									#275
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Not sure if it is contradictory, but some info seems to be missing.

	27-10-2002 11:00									#276
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Well, I got 0 = 1 when I was working out the problem . I can't see anything wrong with how I set up the problem, so I'm pretty sure that one of the stated proportionalities is screwed up.

	27-10-2002 11:40									#277
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Okay, since you are sure, go ahead and post a question.

	27-10-2002 16:39									#278
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r = rate of falling snow (unknown)
ts = when snow has started falling (which we want)
p = plows constant rate of removing snow (unknown)

snow depth at time t: s = r*(t-ts)
speed of plow: v = p/s
which gives us v = p/(r*(t-ts))

Thus speed on first hour is integral from 4pm to 5pm:
v1 = (p/r)*log((5-ts)/(4-ts))
And for the second hour:
v2 = (p/r)*log((6-ts)/(5-ts))
We know that
v1 = 2*v2
So:
(p/r)*log((5-ts)/(4-ts))=(p/r)*log((5-ts)/(4-ts))
Get rid of (p/r):
log((5-ts)/(4-ts))=log((6-ts)/(5-ts))
Get rid of log:
(5-ts)/(4-ts)=((6-ts)/(5-ts))^2
Which simplifies down to:

ts^2-9ts+19=0

Which gives us roots 5,61 and 3,38 and as it started snowing before 4, only latter makes sense.
Turn .38 into minutes and we have the answer: 3:23 pm

	27-10-2002 18:08									#279
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Heres an easier one:
A bookworm eats from the first page of an encyclopedia to the last page.
The bookworm eats in a straight line.
The encyclopedia consists of ten 1000-page volumes and is sitting on a bookshelf in the usual order.
Not counting covers, title pages, etc., how many pages does the bookworm eat? Including the first and the last page.

Last edited by Ignorance on 27-10-2002 at 18:41

	28-10-2002 00:57									#280
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quote: Originally posted by Urban Ranger But /\II don't mean anything.

No, but it's still two equally big parts.

	28-10-2002 01:35									#281
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quote: Thus speed on first hour is integral from 4pm to 5pm: v1 = (p/r)*log((5-ts)/(4-ts)) And for the second hour: v2 = (p/r)*log((6-ts)/(5-ts))

Distance travelled, not speed.

quote: ))^2

Ack, of course. Forgot the factor of two.

	28-10-2002 01:38									#282
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quote: Originally posted by Ignorance Heres an easier one: A bookworm eats from the first page of an encyclopedia to the last page. The bookworm eats in a straight line. The encyclopedia consists of ten 1000-page volumes and is sitting on a bookshelf in the usual order. Not counting covers, title pages, etc., how many pages does the bookworm eat? Including the first and the last page.

5000?

	28-10-2002 01:46									#283
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It could also be 5010, depending on how many cover pages there are (or where the first "real" page is, on the left or on the right.)

	28-10-2002 01:54									#284
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8002
He eats the entire books 2-9 and one page each from the first and the last book.

	28-10-2002 01:58									#285
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Why only 2-9?

	28-10-2002 02:03									#286
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It starts at the first page of the first book and goes directly into the last page of the second book. When it arrives at the last book it only eats the last page.

	28-10-2002 02:08									#287
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10018

	28-10-2002 02:08									#288
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Here's another one:

It cannot be seen, cannot be felt.
Cannot be heard, cannot be smelt.
It lies behind stars and under hills,
And empty holes it fills.
It comes first and follows after,
Ends life, kills laughter.

	28-10-2002 02:09									#289
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death

	28-10-2002 02:10									#290
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nope

	28-10-2002 02:11									#291
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I would think the answer would be ten thousand, but that just seems too obvious. Am I missing something?

	28-10-2002 02:13									#292
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time

	28-10-2002 02:16									#293
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Nothing?

	28-10-2002 02:18									#294
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quote: Originally posted by Immortal Wombat time

no

	28-10-2002 02:21									#295
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quote: Originally posted by Jaguar Warrior Nothing?

If you are immortal. "Nothing ends life"

	28-10-2002 02:32									#296
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I mean, "not counting covers, title pages, etc.," the bookworm eats 1000 pages from each of the ten volumes, for a total of 10,000. It sounds like a simple word problem to me...

	28-10-2002 02:42									#297
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quote: Originally posted by JohnM2433 I mean, "not counting covers, title pages, etc.," the bookworm eats 1000 pages from each of the ten volumes, for a total of 10,000. It sounds like a simple word problem to me...

Take a look in your bookshelves how the books are positioned

	28-10-2002 02:43									#298
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8004 actually. Every page has 2 sides.
For those of you who thought of 10000, think how the books are in the shelv and where the first and last page actually end up.

	28-10-2002 02:58									#299
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quote: 8004 actually. Every page has 2 sides. For those of you who thought of 10000, think how the books are in the shelv and where the first and last page actually end up.

i still don't get it, my first guess would be 5000

	28-10-2002 03:13									#300
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Follow the yellow line, please

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