25-10-2002 02:52									#211
	Got spare money?

It has to do with sales tax, they can chare you an extra penny in tax, but to the government they don't have to claim that penny.

Doesn't seem like a lot until you consider that McDonald's, for instance, is doing this to EVERY customer in EVERY store in the world that has a sales tax.

Sounds good to me anyway.



Who knows?

	25-10-2002 05:36									#212
	Support Apolyton, buy Alpha Centauri

quote: Originally posted by Immortal Wombat I spend much of my Sundays pondering this. It struck me that if you price things just under an amount, people are likely to pay that amount. (eg. £4.99, people give you a fiver) you give a penny change. This is a damn sight easier than pricing stuff at £5.01, and giving 99p change when they give you £6, or more likely, £4.99 change when they give you a tenner.

It is to do with change, think about what could happen in stores if things were priced in round pounds/dollars.

Oh, it has nothing to do with taxes.

	25-10-2002 05:40									#213
	Support Apolyton or Terrorists Win

er... Pretty much obsoletes the smaller denomination of coins. People would get change solely in round £/$, and will be unable (or at least unwilling) to use vending machines.

	25-10-2002 05:51									#214
	Get a bigger avatar today!

You work at a till, or at least you did. Now assume you are an unscrupulous till operator. Someone wants to buy a £5 item, they give you a £5 note....

	25-10-2002 06:09									#215
	Full PM-box? Change here!

...I give them the item, take the money, and oooh I see...

I think

	25-10-2002 06:11									#216
	Remove this text

To give customer change will require the till to be opened - thus ensuring the recording of a transaction.

	25-10-2002 06:17									#217
	Support Apolyton, pre-order Civilization IV

oooh, cunning.

Most till operators are too stupid to figure that out. They just lift it from the till.

Anyway, Paul Hanson's turn then?

	25-10-2002 17:48									#218
	Help yourself to an AD-FREE life

Did he flee?

	25-10-2002 18:48									#219
	Support Apolyton, buy Galactic Civilizations: Deluxe Edition

^bump^

	25-10-2002 19:42									#220
	Help yourself to an AD-FREE life

Alright, since that bugger Paul Hanson has fled the scene, I'll fill in with a silly question.

How do you divide a square into seven equal parts?

	25-10-2002 19:50									#221
	Lose 30 kilos (of popups)

Oops, sorry. Didn`t realise. Not that I'd have come up with anything remotely taxing anyway, so it's probably beneficial to you all that I left when I did.

	25-10-2002 20:07									#222
	Support Apolyton buy from Amazon

Divide the perimeter by 7, and draw lines to the middle.

100*100 square, cut the perimeter into 57 pixel lengths (ish...) and draw lines to the middle. Each segment has the same area.

Attachment: square by 7.gif
This has been downloaded 77 time(s).

	25-10-2002 20:11									#223
	Increase Your PM Length

I suppose that can work, how about a simpler, more elegant way?

	25-10-2002 20:14									#224
	Browse Apolyton AD-FREE

What's not simple? My way works for every number as well, not just 7

	25-10-2002 20:22									#225
	Support Apolyton, buy Alpha Centauri

Of course. So does the one I have in mind.

	25-10-2002 20:57									#226
	Support Apolyton, buy Galactic Civilizations: Deluxe Edition

oh common , UR.

you take one of the sides of the square, and place perpendiculary 6 lines in equal distances from each other, and the other sides of the square.

I would draw it, but it's so plain that it sucks.

	25-10-2002 21:13									#227
	Support Apolyton, buy GURPS/ Alpha Centauri

*slaps self*

	25-10-2002 21:15									#228
	Support Apolyton, buy Civilization III: Complete

quote: Originally posted by Azazel oh common , UR. you take one of the sides of the square, and place perpendiculary 6 lines in equal distances from each other, and the other sides of the square. I would draw it, but it's so plain that it sucks.

Dang you

Your turn for a question.

	25-10-2002 21:41									#229
	Support Apolyton, buy Civilization 2

hmmmm.

I can't think of nothing out of the blue, so I'll skip this turn. actually, IW should ask the question, since he answered first.

	25-10-2002 21:56									#230
	Full PM-box? Change here!

ok, I think I managed to scrape something up.

take 3 squares and place them together like this:

code:

[][]
[]

	25-10-2002 22:58									#231
	Inflate your Upload Space

Like this:

code:

[][]()()
[]{}{}()
/\{}
/\/\

	26-10-2002 01:10									#232
	Increase Your PM Length

Since Azazel seems to have left (and because I know that my answer is correct ), here's the next riddle.

One day Ming was careless enough to leave the forums unattended for a while. When he came back, he found that a lot of new people had arrived. Of these, 63 were simply screaming for a ban.
There were no DLs among the 63.
All 63 fell into at least one, possibly two or three, of these categories: Threadjacker, flamer, spammer.
There was a total of 42 spammers.
There was a total of 20 threadjackers.
There was a total of 30 flamers.
There was 5 people who were both spammers, flamers, and threadjackers.
All people who were flamers and threadjackers were also spammers.
There was twice as many people who were only spammers, as there was people who were only threadjackers.

How many people were only flamers?

	26-10-2002 01:38									#233
	Help yourself to an AD-FREE life

i know it.
but i don't have a riddle, so i'll just shut up

	26-10-2002 02:13									#234
	Help yourself to an AD-FREE life

Mmmkay...

Everyone, just go on without me. I'm going to bed. G'night.

	26-10-2002 02:19									#235
	Help yourself to an AD-FREE life

18 flamers only
30 spammers
15 threadjackets

	26-10-2002 02:20									#236
	Suffering from ads?

Is that correct?

	26-10-2002 02:25									#237
	Support Apolyton buy from Amazon

Exactly 12 people were only flamers.

	26-10-2002 02:34									#238
	Full PM-box? Change here!

12 can't be right.

That would leave 51 others, from which you would end up with 34 only spammers and 17 only threadjackers. If 5 are threadjackers, spammers, and flammers tha would yeild 22 threadjackers (5+17) total, not 20.

	26-10-2002 02:41									#239
	Support Apolyton buy from Amazon

Japher, I'm almost certain my answer is correct. I checked my math very thoroughly. I that found a nice Venn diagram helps to solve this problem. Just so that you can confirm it, though, I got:

18 people are only spammers
9 people are only threadjackers
12 people are only flamers
6 people are both spammers and threadjackers, but not flamers.
13 people are both smammers and flamers, but not threadjackers.
No one is both a threadjacker and a flamer, but not a spammer.
The remaining 5 people are threadjackers, spammers, and flamers.

I suppose that if you interpretted "There was 5 people who were both spammers, flamers, and threadjackers" to mean at least 5 people, rather than exactly 5, more than one correct answer might be possible.

So...

There are two words in the English language that both begin and end with "he". What are they?

If you only get one, feel free to post it by itself and let someone else get the other one.

	26-10-2002 02:54									#240
	Increase Your PM Length

quote: Originally posted by Japher 12 can't be right. That would leave 51 others, from which you would end up with 34 only spammers and 17 only threadjackers. If 5 are threadjackers, spammers, and flammers tha would yeild 22 threadjackers (5+17) total, not 20.

The non-flamers are not all only spammers or only threadjackers. Indeed, if they were, then the flamers would have to be only flamers as well, since no threadjacker or spammer would be a flamer. That would contradict the given statement that "There was 5 people who were both spammers, flamers, and threadjackers". And it would make no sense to add that figure to the number of people who are only threadjackers, since all 63 have already been accounted for.