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NeOmega
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Play Pentagenesis Beta!
Feb 2002 time: 21:23
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^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
Dude..... Why? I'm not wasting my time on that one.
Double doh.... I saw the new riddle was up, but also knew time was short, I panicked :P
Last edited by NeOmega on 19-10-2002 at 04:40
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JohnM2433
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Milwaukee, Wisconsin
Jul 2002 time: 21:23
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I know how to solve the dwarf problem for any number of dwarves, putting the ones with blue hats on the left and the ones with red hats on the right, even if they do not know how many there are of each hat.
One dwarf stands up against the wall. One by one, the remaining dwarves follow these rules:
1. If all the dwarves by the wall are wearing blue hats, go stand to their right.
2. If all the dwarves by the wall are wearing red hats, go stand to their left.
3. Otherwise, go stand between the dwarves by the wall wearing blue hats and the dwarves by the wall wearing red hats. (The dwarves already in line take this cue to move over, making room for more dwarves.)
It should be clear that no dwarf's actions will change the line's arrangement from the desired one, so when they are all done, it will still be in the desired arrangement. Even with the problem given as it was originally, it didn't even occur to me that they should count the hats; this was what I came up with. Of course, with either strategy, if your fellow dwarves aren't smart enough to figure out what to do, you're doomed. Luckily, you do know where you should go in line when the others are lined up correctly (the "middle", in the general case).
It's impossible to divide up land into five contiguous pieces that all touch each other. In fact, it's impossible to make a 2D map that requires five colors, if only adjacent countries require different colors (IIRC). I think a computer program was used to finally prove that theorem. Four pieces is trivial, unless they have to be the same shape as well as the same size.
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Capt Dizle
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quote: Originally posted by NeOmega
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Your monkey must have been hungrier than mine.
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Capt Dizle
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No, calm down. It's 5.75 inches. Work it out.
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Capt Dizle
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Da momma was six when the baby was born.
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Capt Dizle
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Caught in a flood four moderators are trapped on the wrong side of a river. They will drown unless they can all get across a log to the other side in 17 minutes. The log will only support the weight of two people at once, and it is dark and will require a flashlight to cross. There is only one flashlight. Ming is spry and can cross in one minute, Rah is quick and can cross in 2. But MTG is timid and takes 5 minutes and Markos is fat and requires 10 minutes to get across.
How can all four get across in 17 minutes?
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Zero-Tau
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Elsewhere
Aug 2002 time: 06:23
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First Ming and rah crosses (2 min).
Then Ming returns with the flashlight (1 min).
Then Markos and MTG crosses (10 min).
Rah goes back with the flashlight (2 min).
Then Ming and rah crosses (2 min).
That's 17 minutes total.
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Zero-Tau
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Elsewhere
Aug 2002 time: 06:23
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Well, I've posted a riddle here already, and I don't have one handy right now, so....
First come, first served. First person to post a new riddle gets to continue.
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