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JellyBean
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Ignoring the initial skew caused by the start location (which will become insignificant by the time people are buying large numbers of houses), the greatest nonrandom effect will be from the jail. Certainly, there are cards that advance people to mayfair, king's cross station, etc, but there are also cards that send people to jail, plus the 'go to jail' square, plus the three-doubles rule.
So, people will quite often be starting off from jail, moving the distance shown on two dice. The most likely result from rolling two dice is seven, and the other likely results are clustered around that value. On the board, moving that distance onwards from jail corresponds roughly to the orange set. So, the friend was right. 
The probability of rolling at least one six on n dice is:
1 - (probability of not rolling any sixes on n dice)
The chance of not rolling a six on one dice is 5/6, so the chance of not rolling any sixes on n dice is (5/6)^n. So, the expression given above is:
1 - (5/6)^n
Or, for n = 3, 42%.
A more difficult class of problem involves rolling a dice a certain number of times, and then asking what the probability is of the dice being biased. It's possible to solve, but only if you knew the probability that it was biased before you collected any further data. For example, a simpler problem of the same type:
A bag contains a normal coin and a two-headed coin. You take a coin out, without looking at it, and toss it. It comes up heads. You pick it up, without looking at the reverse side, and toss it again. It comes up heads. You repeat this until it has come up heads a total of n times. What is the probability that it is the two-headed coin?
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Rogan Josh
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Pseudo-random number generators are quite easy to write. Here is one for example (sorry its in FORTRAN77):
quote:
FUNCTION RAN1(I)
C-----------------------------------------------------------------------
C MAIN RANDOM NUMBER GENERATOR
C USES METHOD OF l'Ecuyer, (VIA F.JAMES, COMP PHYS COMM 60(1990)329)
C-----------------------------------------------------------------------
IMPLICIT NONE
DOUBLE PRECISION RAN1,HWRSET,HWRGET
INTEGER I,ISEED(2),K,IZ,JSEED(2)
SAVE ISEED
DATA ISEED/12345,67890/
K=ISEED(1)/53668
ISEED(1)=40014*(ISEED(1)-K*53668)-K*12211
IF (ISEED(1).LT.0) ISEED(1)=ISEED(1)+2147483563
K=ISEED(2)/52774
ISEED(2)=40692*(ISEED(2)-K*52774)-K*3791
IF (ISEED(2).LT.0) ISEED(2)=ISEED(2)+2147483399
IZ=ISEED(1)-ISEED(2)
IF (IZ.LT.1) IZ=IZ+2147483562
RAN1=DBLE(IZ)*4.656613001013252D-10
RETURN
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Writing a true random numbe generator is, of course, impossible.
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Yes Orange, computer simulations proved not long ago taht Kentucky is the most landed on property in a game of Monopoly, not long ago.
Although your basic argument is correct, the difference in probability is very thin between each, but the effects that teleport you affect it a bit, as the starting position but almost imperceptibly. The oranges ARE often landed upon while coming out of prison which is the most landed on space so he wasnt totally wrong...
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orange
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It doesn't matter what your name is!
Feb 2000 time: 00:31
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quote: Not entirely true, orange. If starting position was chosen randomly and there were no Chance or Community Chest cards, you'd be correct. However, the fact that you always start in one spot does skew Monopoly a bit, as do (obviously) cards that say things like "Go to St. James Place." Consider that Mediterranean & Baltic Ave. are screwed over anyway not just because they have only 2 slots, but because you're less likely to hit them in your initial pass around the board. Not that this matters much, considering that the first pass around the board- when the probabilities are most skewed- is also when nobody owns anything, and therefore arguments about what to buy become more moot. |
quote: Originally posted by LulThyme
Yes Orange, computer simulations proved not long ago taht Kentucky is the most landed on property in a game of Monopoly, not long ago.
Although your basic argument is correct, the difference in probability is very thin between each, but the effects that teleport you affect it a bit, as the starting position but almost imperceptibly. The oranges ARE often landed upon while coming out of prison which is the most landed on space so he wasnt totally wrong... |
Ignoring all chance and community chest...we're talking straight dice rolls...and the only one that can't be landed on is the first one.
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Curiosity
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Try this problem -
A man on a gameshow chooses from three boxes, one of which contains a prize. The gameshow host then opens one of the other two boxes, showing that it's empty. The man is offered the chance to change his choice to the remaining box, or stick with the one he chose in the first place.
What should he do, and does it make any difference?
Quite a basic problem in probability, but many mathematicians have trouble with it.
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yavoon
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quote: Originally posted by Curiosity
Try this problem -
A man on a gameshow chooses from three boxes, one of which contains a prize. The gameshow host then opens one of the other two boxes, showing that it's empty. The man is offered the chance to change his choice to the remaining box, or stick with the one he chose in the first place.
What should he do, and does it make any difference?
Quite a basic problem in probability, but many mathematicians have trouble with it. |
always switch. switching is 2/3rds. many ways to explain it. but the way I like is that.
If u pick the right box initially then the host removes half the wrong boxes. if u pick the wrong box initially then the host removes all remaining incorrect boxes.
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yavoon
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quote: Originally posted by chegitz guevara
Irrelevent. You need doubles to get out of jail, so the probabilities are evenly distributed. |
incorrect. u need doubles, 50$ or a get out of jail free card.
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orange
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It doesn't matter what your name is!
Feb 2000 time: 00:31
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quote: u land on it more than purple because higher 2d #'s are easier to attain than lower 2d #'s. |
Huh? Equal chance of rolling a 2, 3, 4, 5, or 8 (non-orange as it is of roling a 7, 9, or 10 (orange) from Jail.
Also - there are 9 and 9 types of rolls that are greater and less than 7, and 3 types of rolls that are equal to 7
1,1 < 7
1,2 < 7
1,3 < 7
1,4 < 7
1,5 < 7
2,2 < 7
2,3 < 7
2,4 < 7
3,3 < 7
1,6 = 7
2,5 = 7
3,4 = 7
2,6 > 7
3,5 > 7
3,6 > 7
4,4 > 7
4,5 > 7
4,6 > 7
5,5 > 7
5,6 > 7
6,6 > 7
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